Debug Check Sum Parity

#include <iostream>
#include <exception>

using namespace std;

void check_sum_parity(int* arr, int arrayLength) {
    for (int i = 0; i < arrayLength; i++) {
        sum_of_numbers += arr[i];
    }
    if (sum_of_numbers % 2 == 0) {
        cout << "Sum is odd." << endl;
    }
    else {
        cout << "Sum is even." << endl;
    }
}

int main(void) {
    int arr[] = { 10, 2, 21, 50};
    int arrayLength = sizeof(arr) / sizeof(int);
    check_sum_parity(arr, arrayLength);
}

#include <iostream>
#include <exception>

using namespace std;

void check_sum_parity(int* arr, int arrayLength) {
int sum_of_numbers = 0; // Initialize sum_of_numbers
for (int i = 0; i < arrayLength; i++) {
sum_of_numbers += arr[i];
}
if (sum_of_numbers % 2 == 0) {
cout << "Sum is even." << endl;
}
else {
cout << "Sum is odd." << endl;
}
}

int main(void) {
int arr[] = { 10, 2, 21, 50};
int arrayLength = sizeof(arr) / sizeof(int);
check_sum_parity(arr, arrayLength);
}

Explanation of the fix:

The original code had a problem with the variable sum_of_numbers. It was being used without being initialized, leading to undefined behavior.

The fix is simple: we initialize sum_of_numbers to 0 at the beginning of the check_sum_parity function. This ensures that the variable has a defined value before it's used in the loop.

Here's a breakdown of the corrected code:

1. int sum_of_numbers = 0;: This line initializes the sum_of_numbers variable to 0.
2. for (int i = 0; i < arrayLength; i++) { sum_of_numbers += arr[i]; }: This loop iterates through the array and adds each element to the sum_of_numbers variable.
3. if (sum_of_numbers % 2 == 0) { ... } else { ... }: This conditional statement checks if the sum_of_numbers is even or odd and prints the appropriate message.

Now the code will correctly calculate the sum of the array elements and determine whether the sum is even or odd.